Modified Microwave Transformer

               I started with one of my salvaged microwave transformers. (I have been studying electrical theory for four years in high school and college. Do not try this at home.)  I removed the secondary coil which has 100s more turns than the primary (the turn ratio is what determines the output voltage). Unmodified, the turn ratio is about 1 : 20, meaning if you start with 120 volts, the output is 2400 volts. I have modified the turn ratio to be 1 : .01, now, a 120-volt input will yield a 1.2-volt output. The power of a transformer does not change, the equation for power in term of voltage and current is P = I (E), (E=voltage, I=current). In the unmodified case, the voltage was very high. This means that the current must be low to satisfy our power requirement. In the modified case, the voltage is very low, therefore the current must be high. Since the voltage is extremely low, it is harmless.  This is demonstrated in the video. The reason the coin melted and my fingers did not is because the resistance of the coin is very, very small relative to my fingers. If we do the math using the equation E = I (R), If E is 1.2-volts and R (resistance) = 1.2 mega ohms, the current will be .000001 amps which is practically nothing. If we consider the coin to have a resistance of .0015 ohms, we see the potential current is 800 amps. The reason I hesitated when touching the wires was out of fear of a temperature burn.